Consider the reaction sequence given below. W | vedclass

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(A) Reaction $(1)$ is an $SN_{1}$ reaction. The rate law is given as $	ext{rate} = k[t-BuBr]$. Since the rate is independent of the concentration of

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Changing the concentration of base will have no effect on reaction $(1)$.

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(A) Reaction $(1)$ is an $SN_{1}$ reaction. The rate law is given as $	ext{rate} = k[t-BuBr]$. Since the rate is independent of the concentration of the nucleophile/base,changing the concentration of the base will have no effect on reaction $(1)$.Reaction $(2)$ is an $E_{2}$ reaction. The rate law is given as $	ext{rate} = k[t-BuBr][OH^{\ominus}]$. Since the rate depends on the concentration of the base,changing the concentration of the base will affect the rate of reaction $(2)$.Therefore,the statement that changing the concentration of base will have no effect on reaction $(1)$ is true.

Consider the reaction sequence given below. Which of the following statements is true?

Similar Questions

The decreasing order of the rate of $S_{N^1}$ reaction for the following compounds is:
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$IV$. $Ph-CH_2Br$

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The following order can be correct for:
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